3.365 \(\int \frac {\csc (x) \sin (3 x)}{c+d x} \, dx\)

Optimal. Leaf size=57 \[ \frac {2 \cos \left (\frac {2 c}{d}\right ) \text {Ci}\left (\frac {2 c}{d}+2 x\right )}{d}+\frac {2 \sin \left (\frac {2 c}{d}\right ) \text {Si}\left (\frac {2 c}{d}+2 x\right )}{d}+\frac {\log (c+d x)}{d} \]

[Out]

2*Ci(2*c/d+2*x)*cos(2*c/d)/d+ln(d*x+c)/d+2*Si(2*c/d+2*x)*sin(2*c/d)/d

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Rubi [A]  time = 0.25, antiderivative size = 57, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 5, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.357, Rules used = {4431, 3312, 3303, 3299, 3302} \[ \frac {2 \cos \left (\frac {2 c}{d}\right ) \text {CosIntegral}\left (\frac {2 c}{d}+2 x\right )}{d}+\frac {2 \sin \left (\frac {2 c}{d}\right ) \text {Si}\left (\frac {2 c}{d}+2 x\right )}{d}+\frac {\log (c+d x)}{d} \]

Antiderivative was successfully verified.

[In]

Int[(Csc[x]*Sin[3*x])/(c + d*x),x]

[Out]

(2*Cos[(2*c)/d]*CosIntegral[(2*c)/d + 2*x])/d + Log[c + d*x]/d + (2*Sin[(2*c)/d]*SinIntegral[(2*c)/d + 2*x])/d

Rule 3299

Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[SinIntegral[e + f*x]/d, x] /; FreeQ[{c, d,
e, f}, x] && EqQ[d*e - c*f, 0]

Rule 3302

Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[CosIntegral[e - Pi/2 + f*x]/d, x] /; FreeQ
[{c, d, e, f}, x] && EqQ[d*(e - Pi/2) - c*f, 0]

Rule 3303

Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Dist[Cos[(d*e - c*f)/d], Int[Sin[(c*f)/d + f*x]
/(c + d*x), x], x] + Dist[Sin[(d*e - c*f)/d], Int[Cos[(c*f)/d + f*x]/(c + d*x), x], x] /; FreeQ[{c, d, e, f},
x] && NeQ[d*e - c*f, 0]

Rule 3312

Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sin
[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f, m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1])
)

Rule 4431

Int[((e_.) + (f_.)*(x_))^(m_.)*(F_)[(a_.) + (b_.)*(x_)]^(p_.)*(G_)[(c_.) + (d_.)*(x_)]^(q_.), x_Symbol] :> Int
[ExpandTrigExpand[(e + f*x)^m*G[c + d*x]^q, F, c + d*x, p, b/d, x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && M
emberQ[{Sin, Cos}, F] && MemberQ[{Sec, Csc}, G] && IGtQ[p, 0] && IGtQ[q, 0] && EqQ[b*c - a*d, 0] && IGtQ[b/d,
1]

Rubi steps

\begin {align*} \int \frac {\csc (x) \sin (3 x)}{c+d x} \, dx &=\int \left (\frac {3 \cos ^2(x)}{c+d x}-\frac {\sin ^2(x)}{c+d x}\right ) \, dx\\ &=3 \int \frac {\cos ^2(x)}{c+d x} \, dx-\int \frac {\sin ^2(x)}{c+d x} \, dx\\ &=3 \int \left (\frac {1}{2 (c+d x)}+\frac {\cos (2 x)}{2 (c+d x)}\right ) \, dx-\int \left (\frac {1}{2 (c+d x)}-\frac {\cos (2 x)}{2 (c+d x)}\right ) \, dx\\ &=\frac {\log (c+d x)}{d}+\frac {1}{2} \int \frac {\cos (2 x)}{c+d x} \, dx+\frac {3}{2} \int \frac {\cos (2 x)}{c+d x} \, dx\\ &=\frac {\log (c+d x)}{d}+\frac {1}{2} \cos \left (\frac {2 c}{d}\right ) \int \frac {\cos \left (\frac {2 c}{d}+2 x\right )}{c+d x} \, dx+\frac {1}{2} \left (3 \cos \left (\frac {2 c}{d}\right )\right ) \int \frac {\cos \left (\frac {2 c}{d}+2 x\right )}{c+d x} \, dx+\frac {1}{2} \sin \left (\frac {2 c}{d}\right ) \int \frac {\sin \left (\frac {2 c}{d}+2 x\right )}{c+d x} \, dx+\frac {1}{2} \left (3 \sin \left (\frac {2 c}{d}\right )\right ) \int \frac {\sin \left (\frac {2 c}{d}+2 x\right )}{c+d x} \, dx\\ &=\frac {2 \cos \left (\frac {2 c}{d}\right ) \text {Ci}\left (\frac {2 c}{d}+2 x\right )}{d}+\frac {\log (c+d x)}{d}+\frac {2 \sin \left (\frac {2 c}{d}\right ) \text {Si}\left (\frac {2 c}{d}+2 x\right )}{d}\\ \end {align*}

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Mathematica [A]  time = 0.06, size = 49, normalized size = 0.86 \[ \frac {2 \cos \left (\frac {2 c}{d}\right ) \text {Ci}\left (2 \left (\frac {c}{d}+x\right )\right )+2 \sin \left (\frac {2 c}{d}\right ) \text {Si}\left (2 \left (\frac {c}{d}+x\right )\right )+\log (c+d x)}{d} \]

Antiderivative was successfully verified.

[In]

Integrate[(Csc[x]*Sin[3*x])/(c + d*x),x]

[Out]

(2*Cos[(2*c)/d]*CosIntegral[2*(c/d + x)] + Log[c + d*x] + 2*Sin[(2*c)/d]*SinIntegral[2*(c/d + x)])/d

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fricas [A]  time = 0.44, size = 62, normalized size = 1.09 \[ \frac {{\left (\operatorname {Ci}\left (\frac {2 \, {\left (d x + c\right )}}{d}\right ) + \operatorname {Ci}\left (-\frac {2 \, {\left (d x + c\right )}}{d}\right )\right )} \cos \left (\frac {2 \, c}{d}\right ) + 2 \, \sin \left (\frac {2 \, c}{d}\right ) \operatorname {Si}\left (\frac {2 \, {\left (d x + c\right )}}{d}\right ) + \log \left (d x + c\right )}{d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(x)*sin(3*x)/(d*x+c),x, algorithm="fricas")

[Out]

((cos_integral(2*(d*x + c)/d) + cos_integral(-2*(d*x + c)/d))*cos(2*c/d) + 2*sin(2*c/d)*sin_integral(2*(d*x +
c)/d) + log(d*x + c))/d

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giac [A]  time = 2.95, size = 51, normalized size = 0.89 \[ \frac {2 \, \cos \left (\frac {2 \, c}{d}\right ) \operatorname {Ci}\left (\frac {2 \, {\left (d x + c\right )}}{d}\right ) + 2 \, \sin \left (\frac {2 \, c}{d}\right ) \operatorname {Si}\left (\frac {2 \, {\left (d x + c\right )}}{d}\right ) + \log \left (d x + c\right )}{d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(x)*sin(3*x)/(d*x+c),x, algorithm="giac")

[Out]

(2*cos(2*c/d)*cos_integral(2*(d*x + c)/d) + 2*sin(2*c/d)*sin_integral(2*(d*x + c)/d) + log(d*x + c))/d

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maple [A]  time = 0.06, size = 58, normalized size = 1.02 \[ \frac {2 \Ci \left (\frac {2 c}{d}+2 x \right ) \cos \left (\frac {2 c}{d}\right )}{d}+\frac {\ln \left (d x +c \right )}{d}+\frac {2 \Si \left (\frac {2 c}{d}+2 x \right ) \sin \left (\frac {2 c}{d}\right )}{d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(csc(x)*sin(3*x)/(d*x+c),x)

[Out]

2*Ci(2*c/d+2*x)*cos(2*c/d)/d+ln(d*x+c)/d+2*Si(2*c/d+2*x)*sin(2*c/d)/d

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maxima [C]  time = 0.38, size = 95, normalized size = 1.67 \[ -\frac {{\left (E_{1}\left (\frac {2 i \, d x + 2 i \, c}{d}\right ) + E_{1}\left (-\frac {2 i \, d x + 2 i \, c}{d}\right )\right )} \cos \left (\frac {2 \, c}{d}\right ) - {\left (-i \, E_{1}\left (\frac {2 i \, d x + 2 i \, c}{d}\right ) + i \, E_{1}\left (-\frac {2 i \, d x + 2 i \, c}{d}\right )\right )} \sin \left (\frac {2 \, c}{d}\right ) - \log \left (d x + c\right )}{d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(x)*sin(3*x)/(d*x+c),x, algorithm="maxima")

[Out]

-((exp_integral_e(1, (2*I*d*x + 2*I*c)/d) + exp_integral_e(1, -(2*I*d*x + 2*I*c)/d))*cos(2*c/d) - (-I*exp_inte
gral_e(1, (2*I*d*x + 2*I*c)/d) + I*exp_integral_e(1, -(2*I*d*x + 2*I*c)/d))*sin(2*c/d) - log(d*x + c))/d

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {\sin \left (3\,x\right )}{\sin \relax (x)\,\left (c+d\,x\right )} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sin(3*x)/(sin(x)*(c + d*x)),x)

[Out]

int(sin(3*x)/(sin(x)*(c + d*x)), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sin {\left (3 x \right )} \csc {\relax (x )}}{c + d x}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(x)*sin(3*x)/(d*x+c),x)

[Out]

Integral(sin(3*x)*csc(x)/(c + d*x), x)

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